Hello, this is Kimchiman.
I am not a expert of MHS but it will be helpful information for you who
doesn't know.
#calculate or find a pattern (whatever it is)#
For example, (you need at least 2 or 3 different set of addresses)
assume that you already know A and B cases, and you need to find
C case. How to do it?
..............Running.....Attack1......Attack2
A case: 038551E6 03854BAA 03854BAE
B case: 038551B6 03854B7A 03854B7E
C case: 038551D6
Do you see that first 5digits are same in A,B, and C?
Therefore, first 5digits of att1 of C case must be "03854" and same to
att2 of C case.
..............Running.....Attack1......Attack2
A case: 038551E6 03854BAA 03854BAE
B case: 038551B6 03854B7A 03854B7E
C case: 038551D6 03854( ) 03854( )
How to find rest of digits?
there are patterns. Running address ended up with digit "6"
and last digit of att1 and att2 are "A" and "E"
Therefore, last digit of att1 and att2 must be "A" and "E" too.
..............Running.....Attack1......Attack2
A case: 038551E6 03854BAA 03854BAE
B case: 038551B6 03854B7A 03854B7E
C case: 038551D6 03854 A 03854 E
Do the same 3rd last digit.
3rd last digit for runnings are all "1"
3rd last digit for att1 and att2 are "B" (from A and B cases)
Therefore, 3rd last digit for att1 and att2 must be "B"
..............Running.....Attack1......Attack2
A case: 038551E6 03854BAA 03854BAE
B case: 038551B6 03854B7A 03854B7E
C case: 038551D6 03854B A 03854B E
How to find 2nd last digit?
1)look A case ; 2nd last digit of running is "E"
and 2nd last digits for att1 and att2 are "A"
2)look B case ; 2nd last digit of running is "B"
and 2nd last digits for att1 and att2 are "7"
1)E->A
2)B->7
EDCBA 1) went back by 4. (D C B A)
BA987 2) went back by 4. (A 9 8 7)
Therefore, 2nd last digit of C case must go back by 4 which is "9"
(C B A 9)
..............Running.....Attack1......Attack2
A case: 038551E6 03854BAA 03854BAE
B case: 038551B6 03854B7A 03854B7E
C case: 038551D6 03854B9A 03854B9E
So, this is final addresses for C case.
I wish you understand this. You can submit any addresses with pattern.
You just need at least 2~3 different set of addresses.
ABCDEF0123456789ABCDEF <--- this is num+alp in order.